Find the distance between point A and point B. Enter your answer in the box

A straight line is the shortest distance between two points. The distance between point A and B is 5 units.
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
[tex]D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]
The coordinate of point A is (2,1), while the coordinate of point B is (5,5). Therefore, the distance between points A and B is,
AB = √[(5-2)²+(5-1)²]
= √[3²+ 4²]
= 5 units
Hence, the distance between point A and B is 5 units.
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