Respuesta :
Answer: Thus 4.234 moles of [tex]Ba(OH)_2[/tex] will be produced from the given masses of both reactants.
Explanation:
The balanced chemical reaction is :
[tex]Ba+2H_2O\rightarrow Ba(OH)_2+H_2[/tex]
According to stoichiometry :
1 mole of [tex]Ba[/tex] require = 2 moles of [tex]H_2O[/tex]
Thus 4.234 moles of [tex]Ba[/tex] will require=[tex]\frac{2}{1}\times 4.234=8.468moles[/tex] of [tex]H_2O[/tex]
Thus [tex]Ba[/tex] is the limiting reagent as it limits the formation of product and [tex]H_2O[/tex] is the excess reagent as it is present in more amount than required.
As 1 mole of [tex]Ba[/tex] give = 1 mole of [tex]Ba(OH)_2[/tex]
Thus 4.234 moles of [tex]Ba[/tex] will give =[tex]\frac{1}{1}\times 4.234=4.234moles[/tex] of [tex]Ba(OH)_2[/tex]
Thus 4.234 moles of [tex]Ba(OH)_2[/tex] will be produced from the given masses of both reactants.
