Answer:
Option c. is correct
Step-by-step explanation:
The standard deviation is a measure of the amount of dispersion in a set of values.
Mean of a normal distribution (m) = 154
Standard deviation (s) = 15
z-score = 2.2
To find: value (x) that has a z-score of 2.2
z-score is given by [tex]z=\frac{x-m}{s}[/tex]
Put [tex]z=2.2,.m=154,s=15[/tex]
[tex]2.2=\frac{x-154}{15}\\15(2.2)=x-154\\33=x-154\\x=33+154\\=187[/tex]
Option c.is correct
