Answer:
C. 160 minutes
Step-by-step explanation:
The calculation to be made will be to process 20 students
We have, according to the exercise, the following data:
For process 1: Registration table, Number of servers = 1, Time spent = 2 minutes
For process 2: cashier, number of servers = 3, time spent = 10 minutes
For process 3: ID processing station, number of servers = 4, time spent = 20 minutes
Demand rate = 0.125
To solve it, we will look for the capacity that the server has of the previously mentioned processes, calculating the following:
Capacity = Number of students served per minute
We can say that at the registration table we observe:
Time needed to serve 1 student = 2 minutes
Capacity = 0.5 students per minute
With the cashier we analyze the following:
Time needed to serve 1 student = 10 minutes
Number of servers = 3
Capacity = 0.3 students per minute
ID processing station
Time needed to serve 1 student = 20 minutes
Number of servers = 4
Capacity = 0.2 students per minute
When comparing the processes, it is definitely found that the bottleneck is the ID processing station, where it takes more time to serve a student, which leads us to infer that the capacity of the process is comparable to the capacity of the process bottleneck
Process capacity = 0.2 students per minute
Given, demand rate = 0.125 students per minute
We observe that the demand rate is less than the capacity of the process, therefore we can infer that the number of students served during each minute is the same as the demand rate.
In this way we find that:
Number of students served per minute = 0.125
Time needed to serve 1 student = 1 / 0.125 = 8 minutes
Time needed to serve 20 students = 8 x 20 = 160 minutes.
We conclude that the answer is that it will take 160 minutes to serve 20 students.
.
Answer:
C) 160 minutes
Explanation:
Given:
Time spent at registration desk = 2mins
Time spent at the cashier = 10 mins
Time spent at the ID processing station = 20 mins
Number of registration desk = 1
Number of cashiers = 3
Number of ID processing stations = 4
Let's calculate the capacity of each process using the expression: number of agents / process time
Therefore,
Capacity of registration desk =
[tex] \frac{1}{2} = 0.5 students per min[/tex]
Capacity of cashiers =
[tex] \frac{3}{10} = 0.3 students per min [/tex]
Capacity of ID processing stations =
[tex] \frac{4}{20} = 0.2 students per min[/tex]
The process capacity is equal to the bottleneck process. Here, the bottleneck process is the process with the longest time per minute which is the ID processing station.
Therefore, given a rate of 0.125 student per min and Process capacity of 0.2 student per min, we'll take 0.125 as the number of students per minute since it is lower than the process capacity.
Therefore, time taken to serve one student = [tex] \frac{1}{0.125} = 8mins [/tex]
Time taken to serve 20 students would be = 20 * 8 = 160 minutes
