Answer:
Step-by-step explanation:
Givens
The average speed is defined as
[tex]s=\frac{d}{t}[/tex]
To finde Javier's speed, we need to transform 75 minutes into hours, we know that 1 hour is equivalent to 60 minutes.
[tex]h=75min \times \frac{1hr}{60min} =1.25 \ hr[/tex]
Now, we find the average speed
[tex]s_{Javier}=\frac{130km}{1.25hr}=104 \ km/hr[/tex]
Therefore, Javier's train travels 104 kilometers per hour.
On the other hand, Serah's traing travels from 9:35 to 12:50, which is equivalent to 3 hours and 15 minutes, but 15 minutes is equivalent to 0.25, so the total time is 3.25 hours, so the average speed is
[tex]s_{Serah}=\frac{377km}{3.25hr}= 116 \ km/hr[/tex]
So, the difference would be
[tex]116-104=12 \ km/hr[/tex]
Therefore, the difference between the average speed is 12 kilometers per hour, where Serah's train has the greatest speed.
