A particular type of cell increases by 75% in number every hour. Find the number of cells present at the end of 12 hours if there are initially 4 of these cells?

Respuesta :

We have been given that a particular type of cell increases by 75% in number every hour. We are asked to find the number of cells present at the end of 12 hours if there are initially 4 of these cells.

We will use exponential growth formula to solve our given problem.

[tex]y=a\cdot (1+r)^x[/tex], where,

y = Final amount,

a = Initial amount,

r = Growth rate in decimal form,

x = Time.

[tex]75\%=\frac{75}{100}=0.75[/tex]

Upon substituting initial value [tex]a=4[/tex] and [tex]x=12[/tex] in above formula, we will get:

[tex]y=4\cdot (1+0.75)^{12}[/tex]

[tex]y=4\cdot (1.75)^{12}[/tex]

[tex]y=4\cdot 825.0050068497657776[/tex]

[tex]y=3300.020027[/tex]

[tex]y\approx 3300[/tex]

Therefore, there will be approximately 3300 cells at the end of 12 hours.

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