A fish bowl contains blue, green and red plastic fish. When a fish is picked out at random, the probability of it being blue is 0.7 and the probability of it being green is 0.2. A prize is given if a red fish is picked out. What is the probability of Matt picking a red fish? (Give your answer as a decimal.) There are 60 fish in the fish bowl. How many of the fish are red?

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Answer:

0.1 probability of Matt picking a red fish

6 of the fish are red.

Step-by-step explanation:

We have these following probabilities:

70% = 0.7 probability that the fish is blue.

20% = 0.2 probability that the fish is green.

p probability that the fish is red.

The sum of all these probabilities is 100% = 1. So

0.7 + 0.2 + p = 1.

p = 0.1

0.1 probability of Matt picking a red fish

There are 60 fish in the fish bowl. How many of the fish are red?

n trials with p probability of sucess. The expected value is

[tex]E(X) = np[/tex]

Here we have [tex]n = 60, p = 0.1[/tex]. So

[tex]E(X) = np = 60*0.1 = 6[/tex]

6 of the fish are red.

The probability of Matt at the time of picking a red fish is 0.1.

And, The number of fish that should be red is 6.

Calculation of the probability:

Since

There is a 70% probability when the fish is blue

And, 20% probability when the fish is green.

Now

Here we assume p be the probability in the case when the fish is red.

So,

Here the sum of probabilities should be 100% i.e. equal to 1.

Now

The following calculation is to be done

0.7 + 0.2 + p = 1

0.9 + p = 1

So,

p = 0.1

Now for the red one it should be

= 60 (0.1)

= 6

Hence, The probability of Matt at the time of picking a red fish is 0.1.

And, The number of fish that should be red is 6.

Learn more about probability here: https://brainly.com/question/10695144