Respuesta :
Answer:
I. The balloon has a volume of 22.4L
III. The balloon contains 6.022x10^23 molecules.
Explanation:
At stp, it has been proven that 1mole of a gas occupy 22.4L.
Therefore, option (i) is correct.
The molar mass N2 = 14.01 x 2 = 28.02g/mol
Number of mole of N2 = 1 mole
Mass of N2 =..?
Mass = mole x molar Mass
Mass of N2 = 1 x 28.02 = 28.02g.
The mass content of the balloon is 28.02g, therefore, option (ii) is wrong.
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of N2 also contains 6.02x10^23 molecules
Therefore, option (iii) is correct.
The correct options to the question are:
Option i and option iii
Answer:
I and III are correct
Explanation:
Hello,
In this case, I. and III. are true since:
I. the STP conditions are referred to 273 K and 1 atm, therefore the volume is:
[tex]V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}*273K}{1atm}=22.4L[/tex]
II. In 1 mole of nitrogen (N₂) there are 28.02 g as it is diatomic, therefore this is false.
III. 1 mole of a substance, in this case nitrogen, equals 6.022x10²³ (Avogadro's number) particles, in this case molecules
Best regards.