A 12​-tooth gear on a motor shaft drives a larger gear having 42 teeth. If the motor shaft rotates at 700 ​rpm, what is the speed of the larger​ gear? The speed of the larger gear is nothing rpm.

Respuesta :

Answer:

203 rpm

Step-by-step explanation:

The speed of the larger gear can be calculated using the following equation:

[tex] v = \omega*R [/tex]  

Where:

ω: is the angular velocity of the motor = 700 rpm

R: is the gear ratio

The gear ratio is the following:

[tex] R = \frac{n_{(a)}}{n_{(b)}} [/tex]  

Where:

n(a): is the number of teeth on the small gear = 12 teeth  

n(b): is the number of teeth on the larger gear = 42 teeth

The gear ratio is:

[tex]R = \frac{12}{42} = 0.29[/tex]

Now, the speed of the larger gear is:

[tex]v = \omega*R = 700 rpm*0.29 = 203 rpm[/tex]

Therefore, the speed of the larger gear is 203 rpm.

I hope it helps you!