Answer:
[tex]x^2+18=-9x : x = -3, x = -6[/tex]
Step-by-step explanation:
[tex]x^2+18=-9x[/tex]
Add 9x to both sides:
[tex]x^2+18+9x=-9x+9x[/tex]
Simplify:
[tex]x^2+9x+18=0[/tex]
Solve with the quadratic formula:
For a quadratic equation of the form [tex]ax^2+bx+c=0[/tex] the solutions are:
[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
For [tex]a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}[/tex]
[tex]x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3[/tex]
[tex]x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6[/tex]
The solution to the quadratic equation are:
[tex]x=-3,\:x=-6[/tex]
Hope I helped. If so, may I get brainliest and a thanks?
Thank you, have a good day!
