Which two ordered pairs generated by x = y2 - 1 can be used to show that the
equation is not a function?
(0,-1) and (-1,0)
(-3,-2) and (24,-5)
(8,3) and (8,-3)
(3, 2) and (15,4)​

Respuesta :

Answer: (8,3) and (8,-3)

Step-by-step explanation:

This is because there can not be 2 repeating x values (the line test)

Option C is correct - (8, 3) and (8,-3)

We have a linear equation in two variables as - [tex]x = y^{2} - 1[/tex]

We have to find out which ordered pairs of the mentioned are sufficient to prove that the equation is not a function.

In which condition an equation is not a function?

Plot the graph of the equation, if for one value of x more than one value of y exists then the equation is not a function.

The equation given to us - [tex]x = y^{2} - 1[/tex]

[tex]x +1 = y^{2}[/tex]

Now, we have to find out for what value of x and y, the equation is not a function -

For the coordinates (8, 3) and (8, -3) -

8 + 1 = 3 x 3 = 9

and

8 + 1 = -3 x -3 = 9

But, here for one value of x =8, we have two values of y = 3, -3, which is never possible in a function. Hence, Option C is correct.

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