Respuesta :
x^4-81 =
(x^2-9)(x^2+9) =
(x+3)(x-3)(x^2+9)
There are two real roots (at x=3,-3).
(x^2-9)(x^2+9) =
(x+3)(x-3)(x^2+9)
There are two real roots (at x=3,-3).
Answer:
Find roots of x4−81=0 by solving for x. x=3,−3
Step-by-step explanation: