Answer:
[tex]y = 1[/tex]
Explanation:
[tex] {y}^{2} + 14 = 3 {y}^{2} \times 5 \\ {y}^{2} + 14 = 15 {y}^{2} \\ {y}^{2} - 15 {y}^{2} = - 14 \\ - 14 {y}^{2} = - 14 \\ \frac{ - 14 {y}^{2} }{ - 14} = \frac{ - 14}{ - 14} \\ {y}^{2} = 1 \\ y = \sqrt{1} \\ y = 1[/tex]
