Respuesta :

ranau1199

Answer:

[tex]y=1,\:y=-1[/tex]

Step-by-step explanation:

[tex]y^2+14=3y^2\cdot \:5\\\y^2+14-14=3y^2\cdot \:5-14\\y^2=15y^2-14\\y^2-15y^2=15y^2-14-15y^2\\-14y^2=-14\\\frac{-14y^2}{-14}=\frac{-14}{-14}\\y^2=1\\\\y=\sqrt{1},\:y=-\sqrt{1}\\y=1,\:y=-1[/tex]

Answer:

y = ± 1

Step-by-step explanation:

Given

y² + 14 = 3y² × 5, that is

y² + 14 = 15y² ( subtract y² from both sides )

14 = 14y² ( divide both sides by 14 )

1 = y² ( take the square root of both sides )

± [tex]\sqrt{1}[/tex] = y , that is

y = ± 1

Thus y = - 1 or y = 1

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