Solve the following quadratic for the values x

Answer:
x² + 6x - 27 = 0
x² + 9x - 3x - 27 = 0
x ( x + 9 ) - 3 ( x + 9 ) = 0
( x + 9 ) ( x - 3 ) = 0
Thus ,
x = -9 or x = 3
I hope it helps you
#Indian : )
[tex] {x}^{2} + 6x - 27 = 0 \\ D= {6}^{2} - 4 \times ( - 27) = 36 + 108 = 144 = {12}^{2} \\ x_1= \dfrac{ - 6 + 12}{2} = 3 \\ x_2= \dfrac{ - 6 - 12}{2} = - 9[/tex]
Answer: x=3; x=-9