An object is moving at a velocity of 3m/s. It accelerates to a velocity of 5.5m/s over a time of 9 s. What acceleration did it experience?

Respuesta :

Answer:

Acceleration(a) = [tex]\displaystyle\frac{v - u}{t}[/tex]

v = final velocity = 5.5 m/s

u = initial velocity = 3 m/s

t = time = 9s

[tex]\displaystyle a = \frac{3-5.5}{9}[/tex]

[tex]a = \displaystyle\frac{-2.5}{9}[/tex]

[tex]a = -0.278 \ m/s^2[/tex] (approx)

Answer:

The acceleration experienced by the object when moved over a time of 9 seconds with its velocity is 0.277m/s^2

Explanation:

Acceleration is the rate of change of velocity

The change in velocity implies that the object moves with an initial velocity and stopped with a final velocity.

The object move with a velocity of 3.0m/s

This implies that the initial velocity of the moving object was 3m/s

The object gets to its final position over a time of 9 seconds with a velocity of 5.5m/s

[tex]a = \frac{v - u}{t} \\Where,\\v = final velocity\\u = initial velocity\\t = time\\\\u = 3m/s\\v = 5.5m/s\\t =9 secs\\\\a = \frac{5.5 - 3}{9} \\\\a = \frac{2.5}{9} \\a= 0.277 m/s^{2}[/tex]