Respuesta :
Answer:
Acceleration(a) = [tex]\displaystyle\frac{v - u}{t}[/tex]
v = final velocity = 5.5 m/s
u = initial velocity = 3 m/s
t = time = 9s
[tex]\displaystyle a = \frac{3-5.5}{9}[/tex]
[tex]a = \displaystyle\frac{-2.5}{9}[/tex]
[tex]a = -0.278 \ m/s^2[/tex] (approx)
Answer:
The acceleration experienced by the object when moved over a time of 9 seconds with its velocity is 0.277m/s^2
Explanation:
Acceleration is the rate of change of velocity
The change in velocity implies that the object moves with an initial velocity and stopped with a final velocity.
The object move with a velocity of 3.0m/s
This implies that the initial velocity of the moving object was 3m/s
The object gets to its final position over a time of 9 seconds with a velocity of 5.5m/s
[tex]a = \frac{v - u}{t} \\Where,\\v = final velocity\\u = initial velocity\\t = time\\\\u = 3m/s\\v = 5.5m/s\\t =9 secs\\\\a = \frac{5.5 - 3}{9} \\\\a = \frac{2.5}{9} \\a= 0.277 m/s^{2}[/tex]