Answer:
The probability that the number on the chip is greater than or equal to 24 is 0.531 or [tex]\frac{26}{49}[/tex]
Step-by-step explanation:
Given
Same Sized Chips
Number of Chips = 49
Required
The probability that the number on the chip is greater than or equal to 24
Given that all 49 chips are same sized, the means that they have equal probabilities;
Let C represent the event;
Hence, [tex]n(C\geq 24)[/tex] represents the chips numbered 24 and above
We're to calculate [tex]P(C\geq 24)[/tex] which represents the probability of obtaining a chip numbered 24 and above
[tex]P(C\geq 24) = \frac{n(C\geq 24)}{Total-chips}[/tex]
Chips numbered 24 and above are 24, 25, 26......49 and they're 26 in total
So, [tex]n(C\geq 24) = 26 chips[/tex]
[tex]P(C\geq 24) = \frac{n(C\geq 24)}{Total-chips}[/tex]
becomes
[tex]P(C\geq 24) = \frac{26}{49}[/tex]
[tex]P(C\geq 24) = 0.5306122449[/tex]
[tex]P(C\geq 24) = 0.531[/tex] -- approximated
Hence, the probability that the number on the chip is greater than or equal to 24 is 0.531 or [tex]\frac{26}{49}[/tex]
