Answer:
[tex]7x+\frac{1}{4}\\or\\7x+\frac{1}{4}=0\quad :\quad x=-\frac{1}{28}[/tex]
Step-by-step explanation:
[tex]5x+\frac{3}{4}+2x-\frac{1}{2}=7x+\frac{1}{4}\\5x+\frac{3}{4}+2x-\frac{1}{2}\\5x+2x+\frac{3}{4}-\frac{1}{2}\\7x+\frac{3}{4}-\frac{1}{2}\\7x+\frac{3}{4}-\frac{2}{4}\\7x+\frac{1}{4}\\or\\7x+\frac{1}{4}=0\quad :\quad x=-\frac{1}{28}[/tex]
