Answer:
[tex]p = \frac{3}{11}[/tex]
Step-by-step explanation:
We have these following probabilities:
3/11 probability of choosing a green sweet.
5/11 probability of choosing a red sweet.
p probability of choosing a yellow sweet.
The sum of these probabilities is decimal 1. So
[tex]p + \frac{3}{11} + \frac{5}{11} = 1[/tex]
[tex]\frac{11p + 3 + 5}{11} = 11[/tex]
[tex]11p + 8 = 11[/tex]
[tex]11p = 3[/tex]
[tex]p = \frac{3}{11}[/tex]
Answer:
the probability of choosing a yellow sweet from the bag is [tex]\frac{3}{11}[/tex]
Step-by-step explanation:
Given that;
The probability of choosing a green sweet at random from the bag is 3/11 the probability of choosing a red sweet at random from the bag is 5/11
probability of choosing a green sweet. is 3/11
probability of choosing a red sweet. is 5/11
probability of choosing a yellow sweet is x
we sum the probabilitity of green and red sweet
[tex]\frac{3}{11} + \frac{5}{11} = \frac{8}{11}[/tex]
To get the probability of choosing a yellow sweet
we subract the sumation of (probabilitity of green and red sweet) and 1
i.e 1 - 8/11
[tex]x =1-\frac{8}{11}[/tex]
= [tex]\frac{3}{11}[/tex]
Thus ,the probability of choosing a yellow sweet from the bag is [tex]\frac{3}{11}[/tex]
