Respuesta :
Answer:
A
Step-by-step explanation:
Given
y = [tex]\frac{x(x+2)}{x(x-3)}[/tex] ← cancel x on numerator/ denominator
= [tex]\frac{x+2}{x-3}[/tex]
Cancelling the factor x, leaves a hole in the graph at x = 0
Answer:
A
Step-by-step explanation:
Given
y = [tex]\frac{x(x+2)}{x(x-3)}[/tex] ← cancel x on numerator/ denominator
= [tex]\frac{x+2}{x-3}[/tex]
Cancelling the factor x, leaves a hole in the graph at x = 0