Respuesta :

Answer:

As E is right angle , CD is hypotenuse , and ED is perpendicular and CE is the base .

Thus sinC = Perpendicular/ Hypotenuse

sinC = ED/CD

sinC = 3/5

The sine of an angle in a right triangle is the ratio of the side opposite to

the angle to the hypotenuse side.

  • [tex]\underline{sin\angle C \ is \ \dfrac{3}{5}}[/tex]

Reasons:

The given parameters of ΔCDE are;

∠E = 90°, DC = 5, CE = 4, ED = 3

Required: The ratio that represents the sine of ∠C

Solution:

Given that ∠E = 90° therefore;

ΔCDE is a right triangle

DC = The hypotenuse side = 5

ED = 3 = The side opposite ∠C

[tex]sin\angle C = \mathbf{\dfrac{Opposite \ leg \ length}{Hypotenuse \ length}}[/tex]

Therefore;

[tex]\underline{sin\angle C \ is \ \dfrac{3}{5}}[/tex]

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