Respuesta :
Answer:
As E is right angle , CD is hypotenuse , and ED is perpendicular and CE is the base .
Thus sinC = Perpendicular/ Hypotenuse
sinC = ED/CD
sinC = 3/5
The sine of an angle in a right triangle is the ratio of the side opposite to
the angle to the hypotenuse side.
- [tex]\underline{sin\angle C \ is \ \dfrac{3}{5}}[/tex]
Reasons:
The given parameters of ΔCDE are;
∠E = 90°, DC = 5, CE = 4, ED = 3
Required: The ratio that represents the sine of ∠C
Solution:
Given that ∠E = 90° therefore;
ΔCDE is a right triangle
DC = The hypotenuse side = 5
ED = 3 = The side opposite ∠C
[tex]sin\angle C = \mathbf{\dfrac{Opposite \ leg \ length}{Hypotenuse \ length}}[/tex]
Therefore;
[tex]\underline{sin\angle C \ is \ \dfrac{3}{5}}[/tex]
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