Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "r" from a collection or a group of distinct objects which we can name "n". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as
[tex]C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}[/tex]
n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) = [tex](\frac{14}{3})[/tex] = [tex]\frac{14!}{(3!(14-3)!)}[/tex]
= [tex]\frac{87178291200}{(6 X 39916800)}[/tex]
= [tex]\frac{87178291200}{239500800}[/tex]
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
