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Hint # 1- Subtract the area of the small rectangle and the area of the triangle from the area of the large rectangle.

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Hint 1 Subtract the area of the small rectangle and the area of the triangle from the area of the large rectangle If you dont know the answer DONT ANSWER I only class=

Respuesta :

Answer:

29 ft^2

Step-by-step explanation:

Let us create a rectangle around this figure, having apparent dimensions 5 by 7 feet. We can conclude the area of the figure by subtracting the non - shaded region from the area of this rectangle;

Area of rectangle ⇒ 5 * 7 = 35 ft^2

Now the non - shaded region can be represented though a triangle, and a rectangle, the triangle having dimensions 2 feet by 2 feet, the rectangle with dimensions 4 feet by 1 foot;

Area of triangle ⇒ 1/2 * base * height = 1/2 * 2 * 2 = 2 ft^2,

Area of mini rectangle ⇒ length * width = 4 * 1 = 4 ft^2

By the Partition Postulate, the area of the shaded region is, consecutively; 35 - 2 - 4 = 29 square feet

Answer: 29 ft^2

Answer:

29ft^2

Step-by-step explanation:

The cut out parts

rectangle [tex]A=lw=4*2=8ft^2[/tex]

triangle [tex]A=\frac{ab}{2} =\frac{2*2}{2} =2ft^2[/tex]

Shaded area

smallest rectangle

[tex]A=lw=3*1=3ft^2[/tex]

Middle rectangle

[tex]A=lw=5*2=10ft^2[/tex]

Biggest rectangle

[tex]A=lw=7*2=14ft^2[/tex]

Shaded triangle equal

[tex]A=\frac{ab}{2} =\frac{2*2}{2} =2ft^2[/tex]

[tex]A_{t}=3+10+14+2=29ft^2[/tex]

hope this helps :)

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