the given graph shows the displacement versus time relation for a disturbance travelling with velocity of 320 m/s. calculate the frequency and wavelength of the disturbance. time(1 millisecond =1ms=10 raised to -3 seconds

frequency is [tex]\frac{1}{t}[/tex] where t is the period, we can tell that the period happens once every 4 seconds. This means that the cycle repeats itself once every 4 seconds. Substituting into the formula we get 1/4.

Now the equation of the wavelength is [tex]\frac{v}{t}[/tex], where v is given as 320 and t we found as 1/4. This means that we times it by 4 to get the answer.

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the given graph shows the displacement versus time relation for a disturbance travelling with velocity of 320 m/s. calculate the frequency and wavelength of the disturbance. time(1 millisecond =1ms=10 raised to -3 seconds​

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the given graph shows the displacement versus time relation for a disturbance travelling with velocity of 320 m/s. calculate the frequency and wavelength of the disturbance. time(1 millisecond =1ms=10 raised to -3 seconds