The diagram represents two small, charged, identical metal spheres, A and B, that are separated by a distance of 2.0 meters. If the two spheres were touched together and then separated, the charge on sphere A would be *
q1= -1.6x10^-6C
q2=+1.0x10^-6 C
d=2m
Final answer is -3.0x10^-7 C, but I don't know why it is like that.

Respuesta :

Answer:

if you are trying to figure out if it is right. I believe it is right (the answer) but trust your instincts go for it.

Explanation:

The charge on sphere A is -3 × 10⁻⁷C.

Distribution of charge:

According to the question, there are two identical spheres, sphere A and sphere B with charges

q₁= -1.6 × 10⁻⁶C , and

q₂=+1.0 × 10⁻⁶ C respectively separated by a distance of 2m.

Now, the charges are brought in contact with each other. So the total charge on both the spheres when they are in contact would be the sum of the two charges, that is:

q = q₁ + q₂

q =  -1.6 × 10⁻⁶C  + 1.0 × 10⁻⁶ C

q =  -0.6 × 10⁻⁶C, or

q = -6 × 10⁻⁷C

Since the two spheres are identical, when they are separated from each other, the charge is distributed equally on both of them. So, the charge on each sphere is :

Q = q/2

Q = (-6 × 10⁻⁷C)/2

Q = -3 × 10⁻⁷C

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