​Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 564 randomly selected adults showed that 56​% of them would erase all of their personal information online if they could. Find the value of the test statistic.

Respuesta :

Answer:

The value of z test statistic is 2.871.

Step-by-step explanation:

We are given that a software firm survey of 564 randomly selected adults showed that 56​% of them would erase all of their personal information online if they could. Find the value of the test statistic.

Let p = population proportion of adults who would erase all of their personal information online if they could.

So, Null Hypothesis, [tex]H_0[/tex] : p [tex]\leq[/tex] 50%      {means that adults who would erase all of their personal information online if they could is less than or equal to 50%}

Alternate Hypothesis, [tex]H_A[/tex] : p > 50%     {means that majority of adults would erase all of their personal information online if they could}

The test statistics that would be used here One-sample z test for proportions;

                            T.S. =  [tex]\frac{\hat p-p}{\sqrt\frac{\hat p(1-\hat p)}{n} {} }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of adults who would erase all of their personal information online if they could = 56%

           n = sample of adults taken = 564

So, the test statistics  =  [tex]\frac{0.56-0.50}{\sqrt\frac{0.56(1-0.56)}{564} {} }[/tex]

                                       =  2.871

The value of z test statistic is 2.871.