Respuesta :
Answer:
21% probability you will hit a green light on monday and a red light on tuesday
Step-by-step explanation:
When two events, A and B, are independent, we have that:
[tex]P(A \cap B) = P(A) \times P(B)[/tex]
In this problem, we have that:
Event A: Green light on monday.
Event B: Red light on tuesday.
The probability that we encounter a green light at the corner of college and main is 0.35
This means that [tex]P(A) = 0.35[/tex]
The probability that we encounter a red light is 0.61:
This means that [tex]P(B) = 0.61[/tex]
These events are independent, that is, the light color on Tuesday is independent of the color on Monday. So
[tex]P(A \cap B) = P(A) \times P(B) = 0.35 \times 0.6 = 0.21[/tex]
21% probability you will hit a green light on monday and a red light on tuesday
