Answer:
[tex] m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]
And replacing we got:
[tex] m =\frac{-3 -3}{-5 +3}= 3[/tex]
Now we can find the intercept using the following general formula:
[tex] y = mx +b[/tex]
And using one of the points we can solve for b and we got:
[tex] 3 = 3*(-3) +b[/tex]
[tex] b = 3 +9 =12[/tex]
And for this case the line cross the y axis since represent the y intercept.
So then the point where the line q cross the y-axis is (0,12)
Step-by-step explanation:
We have two points given :
[tex] (x_1= -3, y_1 = 3)[/tex]
[tex] (x_2= -5, y_2 = -3)[/tex]
We can find the slope of the line like this:
[tex] m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]
And replacing we got:
[tex] m =\frac{-3 -3}{-5 +3}= 3[/tex]
Now we can find the intercept using the following general formula:
[tex] y = mx +b[/tex]
And using one of the points we can solve for b and we got:
[tex] 3 = 3*(-3) +b[/tex]
[tex] b = 3 +9 =12[/tex]
And for this case the line cross the y axis since represent the y intercept.
So then the point where the line q cross the y-axis is (0,12)
Answer:
Step-by-step explanation:
Given that;
[tex]x_1= -3,\\ y_1 = 3, x_2= -5,\\ y_2 = -3[/tex]
slope of the line is
[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]
[tex]m =\frac{-3 -3}{-5 +3}\\\\=\frac{-6}{-2} \\\\= 3[/tex]
To find the intercept we use the formula:
y = mx +b
y = 3
m = 3
x = -3
we can solve for b
[tex]3 = 3\times(-3) +b\\3=-9+b b = 3 +9 =12[/tex]
Therefore, the point where the line q cross the y-axis is (0,12)
