Answer:
The answer is option 3.
Step-by-step explanation:
First, you have to form an equation in a slope-form, y = mx + c where m represents gradient and c is y-intercept. Then substitute the following values into the equation :
[tex]y = mx + c[/tex]
Let m = -3,
Let c = 3,
[tex]y = - 3x + 3[/tex]
Next, in order to find the x-intercept, you have to let y equals to 0 as the line touches x-axis, y will be 0 :
Let y = 0,
[tex] - 3x + 3 = 0[/tex]
[tex] - 3x = - 3[/tex]
[tex]x = - 3 \div - 3[/tex]
[tex]x = 1[/tex]
