Respuesta :

xero099

Answer:

[tex]h(n) = (-5.3)\cdot (-11)^{n-1}[/tex], [tex]\forall n \in \mathbb{N}[/tex]

Step-by-step explanation:

The explicit formula for [tex]h(n)[/tex] is:

[tex]h(n) = (-5.3)\cdot (-11)^{n-1}[/tex], [tex]\forall n \in \mathbb{N}[/tex]

Answer:

first term: -5.3

common factor: -11

This is a geometric sequence hence the equation is the (first term)*[tex](commonfactor)^{n-1}[/tex].

So, the equation is -5.3*[tex](-11)^{n-1}[/tex]

I did it on khan academy:

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