Answer:
See explanation, and ask for more details if unclear!
Step-by-step explanation:
The perfect square of this equation is [tex]x^2-x+\frac{1}{4}[/tex], since the square would be [tex](x-\frac{1}{2})^2[/tex]. 1/4=4/16, meaning that you can set up the equation in the following way:
[tex](x^2-x+\frac{1}{4})-\frac{1}{16}=0[/tex]
[tex](x-\frac{1}{2})^2=\frac{1}{16}[/tex]
Take the square root of both sides:
[tex]x-\frac{1}{2}=\pm \frac{1}{4}[/tex]
Add 1/2 to both sides:
[tex]x=\frac{1}{2}\pm \frac{1}{4}=\frac{3}{4}, \frac{1}{4}[/tex]. Hope this helps!
