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You have 15g of sodium iodide (Nal), which has a molecular weight of 150 g/mol. You place it all in a beaker and fill the beaker to until you have one liter of solution. What is the molarity of the solution?

A. 0.1M

B. 15M

C. 0.15M

D. 0.01M

Respuesta :

dsdrajlin

Answer:

A. 0.1 M

Explanation:

Given data

  • Mass of NaI (solute): 15 g
  • Molar mass of NaI: 150 g/mol
  • Volume of solution: 1 L

Step 1: Calculate the moles of solute

[tex]15g \times \frac{1mol}{150g} = 0.10mol[/tex]

Step 2: Calculate the molarity of the solution

The molarity of the solution is equal to the moles of solute divided by the liters of solution.

[tex]M = \frac{0.10mol}{1L} =0.1M[/tex]

The solution is 0.1 M.

sebassandin

Answer:

A. 0.1M .

Explanation:

Hello,

In this case, we first compute the moles of sodium iodide by using its molar mass:

[tex]n=15g*\frac{1mol}{150g}=0.1mol[/tex]

Then, since the volume of the solution is 1 litre, we can easily compute the molarity:

[tex]M=\frac{n}{V}=\frac{0.1mol}{1L} \\\\M=0.1M[/tex]

Hence, answer is A. 0.1M

Best regards.

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