Answer:
45 inches
Step-by-step explanation:
The product of distances from a point to the two intersections of the secant with the circle is a constant. When the secant is a tangent, the two intersection points have the same distance, so the constant is the square of the tangent length.
Here, we have ...
CD² = CB·CA
14² = 4(4 +BA)
49 = 4 +BA . . . . . . divide by 4
45 = BA . . . . . . . . . subtract 4
The length of the internal segment of the secant is 45 inches.
