Answer:
The value of the current in the wire is 300 A.
Explanation:
The current can be determined by;
B = [tex]\frac{U_{0} I }{2\pi r}[/tex]
Where: B is the magnetic field, I is the current, r id the distance between the wire and sensor and [tex]U_{0}[/tex] is a constant called the permeability of the free space.
From the given question, r = 2 m, B = 3 × [tex]10^{-5}[/tex] T and [tex]U_{0}[/tex] = 4 × [tex]\pi[/tex] × [tex]10^{-7}[/tex] Tm[tex]A^{-1}[/tex]
So that;
I = [tex]\frac{2\pi rB}{U_{0} }[/tex]
= (2 × [tex]\pi[/tex] × 2 × 3 × [tex]10^{-5}[/tex]) ÷ (4 × [tex]\pi[/tex] × [tex]10^{-7}[/tex])
= 300 A
The value of the current in the wire would be 300 A.
