Answer:
1/8
Explanation:
From;
Nt/No = (1/2)^t/t1/2
N= amount of dimethylether present at time t
No= amount of diethylether present at time t=0
t= time taken for N molecules of diethylether to remain = 4710 seconds
t1/2 = half-life of diethylether = 1570 seconds
Substituting values;
Nt/No = (1/2)^4710/1570
Nt/No = (1/2)^3
Nt/No= 1/8
Hence after 4710 seconds only 1/8 molecules of dimethylether will remain
The fraction of an initial amount of dimethylether that remains after 4710. seconds is 1/8.
From the information given, the decomposition of dimethylether at 504℃ is first order with a half-life of 1570 seconds.
Therefore, the fraction of an initial amount of dimethylether that remains after 4710 seconds will be:
= 1/2³
= 1/8
Therefore, the correct option is 1/8.
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