What percentage grade should a road have if the angle of elevation of the road is 6 degrees? (The percentage grade is defined as the change in the altitude of the road over a 100-foot horizontal distance. For example a 5% grade means that the road rises 5 feet for every 100 feet of horizontal distance.)

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Answer:

  10.5%

Step-by-step explanation:

The tangent of the angle is the ratio of rise to run.

  tan(angle) = grade

  tan(6°) ≈ 0.105 = 10.5%

The grade will be 10.5% for an angle of elevation of 6°.

To calculate percent grade simply divide its vertical rise in elevation even by horizontal distance, which gives you a percentage grade estimate.

Rise to run is indicated mostly by angle's tangent.

[tex]\to \bold{\tan(angle) = grade}\\\\\to \bold{\tan (6^\circ)\approx0.105=10.5\%}[/tex]

With an angle of elevation of [tex]\bold{6^{\circ}}[/tex], the grade will be [tex]\bold{10.5 \%}[/tex]

That's why the final answer is "10.5%"

Learn more:

Percentage grade: brainly.com/question/10474633