Answer:
3.48cm³ (approximated)
Step-by-step explanation:
The maximum water that bowl can hold = The volume of the bowl
[tex] \boxed{ \mathsf{volume \: of \: bowl = \frac{2}{3} \times \pi \: r {}^{3} }} [/tex]
Radius is half of diameter.
Given -
From the given data we can derive that the radius of the hemispherical bowl is 5cm (10/2)
Putting the known values into the formula to get the value of the volume of bowl :
[tex] \mathsf{volume = \frac{2}{3} \times \: 3.14 \: \times {5}^{3} }[/tex]
= 3.48888cm³
= 3.48cm³
