Respuesta :
Answer:
Explanation:
It is a case of oscillation by simple pendulum . Expression for simple pendulum is given as follows
T = [tex]2\pi\sqrt{\frac{l}{g} }[/tex]
where T is time period , l is length of pendulum and g is acceleration due to gravity .
[tex]\frac{1}{f} =2\pi\sqrt{\frac{l}{g} }[/tex] , f is frequency of oscillation
For the given case
[tex]\frac{1}{f_o} =2\pi\sqrt{\frac{l}{g} }[/tex]
subsequently length becomes half so
[tex]\frac{1}{f} =2\pi\sqrt{\frac{l}{2g} }[/tex]
dividing
[tex]\frac{f}{f_o} = \sqrt{\frac{2}{1} }[/tex]
f = [tex]\sqrt{2} f_o[/tex]
frequency of oscillation becomes √2 times.
The repetition of the event from the starting event to the end event is called oscillation. The best example of oscillation is the pendullum.
The correction formula is:-[tex]f = \sqrt{2f}[/tex]
The oscillation depends on the following:-
- The length of the string.
The formula of the oscillation is as follows:-
[tex]T = 2\pi\sqrt{\frac{l}{g} }[/tex], In this formula the T is time period, l stands for the Lenght of the string and g stands got the acceleration due to gravity.
The frequency of the oscillation.
[tex]\frac{1}{f} = 2\pi\sqrt{\frac{l}{g} }[/tex]
The frequency of the oscillation for [tex]f_1[/tex]time is:-
[tex]\frac{1}{f_1} = 2\pi\sqrt{\frac{l}{2g} }[/tex]
After diving, the equation is as follows:-
[tex]\frac{f}{f_1} =\sqrt{\frac{2}{1} }[/tex]
Hence, the [tex]f = \sqrt{2f}[/tex]
For more information, refer to the link:-
https://brainly.com/question/2127750
