Answer:
a
The total distance traveled is [tex]D = 26760 \ m[/tex]
b
The average velocity is [tex]v_{avg} = 6.8 \ m/s[/tex]
Explanation:
From the question we are told that
The time taken for first part [tex]t_1 = 22 \ minutes = 22*60 = 1320 \ s[/tex]
The speed for the first part is [tex]v_1 = 7.2 \ m/s[/tex]
The time taken for second part is [tex]t_2 = 36 \ minutes = 2160 \ s[/tex]
The speed for the second part is [tex]v_2 = 5.1 \ m/s[/tex]
The time taken for third part is [tex]t_3 = 8 \ minutes = 480 \ s[/tex]
The speed for the third part is [tex]v_3 = 13 m/s[/tex]
Generally
[tex]distance(D) = velocity * time[/tex]
Therefore the total distance traveled is
[tex]D = (v_1 * t_1) + (v_2 * t_2 ) + (v_3 * t_3)[/tex]
substituting values
[tex]D = (7.2 * 1320) + (5.1 * 2160) + (13 * 480)[/tex]
[tex]D = 26760 \ m[/tex]
Generally the average velocity is mathematically represented as
[tex]v_{avg} = \frac{D}{t_{total}}[/tex]
Where [tex]t_{total}[/tex] is the total time taken which is mathematically represented as
[tex]t_{total} = 1320 + 2160 + 480[/tex]
[tex]t_{total} =3960\ s[/tex]
The average velocity is
[tex]v_{avg} = \frac{26760}{3960}[/tex]
[tex]v_{avg} = 6.8 \ m/s[/tex]
