I’ll teach you how to solve 2(x+2)^2 -5=93
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2(x+2)^2 -5=93
Expand the expression:
2(x^2+4x+4)-5=93
Multiply the parentheses by 2:
2x^2+8x+8-5=93
Subtract the numbers:
2x^2+8x+3-5=93
Move the constant to the left;
2x^2+8x+3-93=0
Calculate:
2x^2+8x-90=0
Divide both sides by 2:
X^2+4x-45=0
Write as a difference:
X^2+9x-5x-45=0
Factor the expressions:
X•(x+9)-5(x+9)=0
Factor the expression:
(X+9)•(x-5)=0
Separate into possible cases:
X+9=0
X-5=0
Solve the equations:
X= -9
X= 5
X= -9, x= 5
Your Answer Is x= -9, x= 5
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