contestada

A potential drop of 50. volts is measured across a
250-ohm resistor. What is the power developed in the
resistor?

Respuesta :

Lanuel

Answer:

Power, P is equal to 10 watts.

Explanation:

Given the following parameters;

Voltage drop, V = 50volts.

Resistance, R = 250ohms.

Power, P =?

The power developed in an electrical circuit is given by;

[tex]P = IV[/tex] ......equation 1

But we also know that;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, V = IR

Making I the subject of formula;

I = V/R

Substituting into equation 1;

[tex]P = (V²)/R[/tex]

P = (50²)/250

P = 2500/250

P = 10 watts.

shubhamchouhanvrVT

Power developed in the resistor will be 10 watts.

Given the following parameters;

Voltage drop, V = 50 volts.

Resistance, R = 250 ohms.

What will be the power developed in the resistor ?

The power developed in an electrical circuit is given by;

[tex]P=VI[/tex]  

According to the ohm's law

Mathematically, V = IR

Making I the subject of formula;

I = V/R

Substituting into equation  [tex]P=VI[/tex]

[tex]P=V\times\dfrac{V}{R}[/tex]

[tex]P=\dfrac{V^{2} }{R}[/tex]

 [tex]p=\dfrac{50^{2} }{250}[/tex]

[tex]P=\dfrac{2500}{250}[/tex]

[tex]P=10[/tex] watts

Hence the Power developed in the resistor will be 10 watts.

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