Respuesta :

Answer:

see explanation

Explanation:

a) Be

b) Cu

c) V

d) Cr

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Lanuel

a. Beryllium (Be) has a larger ionization energy.

b. Copper (Cu) has a larger ionization energy.

c. Vanadium (Va) has a larger ionization energy.

d. Tungsten (W) has a larger ionization energy.

Ionization energy can be defined as the minimum energy required to remove (detach) an electron from a neutral atom in its gaseous state.

In Chemistry, ionization energy generally tend to increase from left to right across a period on the periodic table and from bottom to top in each group of a periodic table.  

Given the following pair of elements:

a. Beryllium (Be) or Barium (Ba).

The ionization energy of beryllium (Be) is 900 kJ/mol.

The ionization energy of barium (Ba) is 503 kJ/mol.

Thus, beryllium (Be) has a larger ionization energy.

b. Copper (Cu) or Radium (Ra)

  • The ionization energy of copper (Cu) is 745 kJ/mol.
  • The ionization energy of radium (Ra) is 509 kJ/mol.

Thus, copper (Cu) has a larger ionization energy.

c. Potassium (K) or Vanadium (Va)

  • The ionization energy of potassium (K) is 419 kJ/mol.
  • The ionization energy of vanadium (Va) is 651 kJ/mol.

Thus, vanadium (Va) has a larger ionization energy.

d. Tungsten (W) or Chromium (Cr)

  • The ionization energy of tungsten (W) is 770 kJ/mol.
  • The ionization energy of chromium (Cr) is 653 kJ/mol.

Thus, tungsten (W) has a larger ionization energy.

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