Answer:
[tex]V_2 = 2.447[/tex] atm
Explanation:
As we know that
[tex]PV = nRT\\[/tex]
Where P is the pressure in atmospheric pressure
T is the temperature in Kelvin
R is the gas constant [tex]R = 0.08206[/tex]
V is the volume in liters
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
Substituting the given values in above equation, we get -
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{5*0.565}{315.15} = \frac{1*V_2}{273}[/tex]
On rearranging, we get
[tex]\frac{5*0.565*273}{315.15} = V_2\\V_2 = 2.447[/tex]
[tex]V_2 = 2.447[/tex] atm
