Answer:
The angular acceleration of the grinding wheel at the given time interval is 3.8 rad/s^2
Explanation:
Given:
Initial time of the grinding wheel, t1 = 0
final time of the grinding wheel, t2 = 10 s
Initial angular velocity of the grinding wheel, u = 0
final angular velocity of the grinding wheel, v = 38 rad/s
The angular acceleration of the wheel between t = 0 s and t = 10 s, is calculated as;
a = dv/dt
Where;
a is angular acceleration
dv is change in angular velocity = v - u = 38 - 0 = 38 rad/s
dt is change in time = t2 - t1 = 10 -0 = 10
a = 38 / 10
a = 3.8 rad/s^2
Therefore, the angular acceleration of the grinding wheel at the given time interval is 3.8 rad/s^2
