Complete part of Question: What is Jane's (and the vine's) angular speed just before she grabs Tarzan
Answer:
Jane's (and the vine's) angular speed just before she grabs Tarzan, w = 1.267 rad/s
Explanation:
According to the law of energy conservation:
Total change in kinetic energy = Total change in potential energy
Mass of Jane = 60 kg
Mass of the vine = 32 kg
Mass of Tarzan = 72 kg
Height of Tarzan = 5.50 m
Length of the vine = 8.50 m
Jane's change in gravitational potential energy,
[tex]U_J = 60 * 9.8 * 5.5\\U_J = 3234 J[/tex]
Vine's gravitational potential energy,
[tex]U_v = Mgh/2\\U_v = 32*9.8*5.5/2\\U_v = 862.4J[/tex]
Vine's Kinetic energy :
[tex]KE_V = 0.5 I w^{2} \\I_V = \frac{ML^2}{3} = \frac{32 * 8.5^2}{3} = 770.67 kg m^2\\ KE_V = 0.5 *770.67 * w^{2}\\KE_V = 385.33 w^{2}[/tex]
Jane's Kinetic energy:
[tex]KE_J = 0.5m(wL)^2\\KE_J = 0.5*60(w * 8.5)^2\\KE_J = 2167.5 w^2[/tex]
[tex]U_J + U_V = KE_J + KE_V[/tex]
3234 + 862.4 = 2167.5w² + 385.33w²
4096.4 = 2552.83w²
w² = 4096.4/2552.83
w² = 1.605
w = √1.605
w = 1.267 rad/s
