Answer:
[tex]\frac{1}{55}[/tex]
Step-by-step explanation:
Total number of tiles: 11 (obtained from counting the letters in probability)
Probability of picking the letter "i" the first time:
There are 2 letter "i's", and 11 total options, so the probability of picking an "i" is:
[tex]\frac{2}{11}[/tex]
Probability of picking the letter "i" the second time:
We now have one less letter in the bag, as the first letter "i" was not replaced.
This means we now only have 1 letter "i", and 10 total options, so the probability of picking the last "i" is:
[tex]\frac{1}{10}[/tex]
When you have two probabilities that are dependant on each other, you multiply them to get the probability of one, given that the other has happened.
Total probability:
[tex]\frac{2}{11}*\frac{1}{10} = \frac{2}{110}[/tex]
Simplify by dividing by 2:
[tex]\frac{1}{55}[/tex]
Answer:
Multiply the fractions/probabilities
2 wanted tiles / 11 tiles in total x 1 wanted tile / 10 total tiles in total = 2/110 chance
2/110 = 1/55 chance
Hope this helps
Step-by-step explanation:
