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The rate of a certain reaction is given by the following rate law: rate k[H2]^2[NH3]Use this information to answer the questions below. What is the reaction order in H2? What is the reaction order in NH3? What is overall reaction order? At a certain concentration of H2 and NH3, the initial rate of reaction is 8.0 x 103 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled? Round your answer to significant digits. The rate of the reaction is measured to be 0.050 M / s when [H2] = 0.66 M and [NH3] = 0.88 M. Calculate the value of the rate constant. Round your answer to significant digits.

Respuesta :

Answer:

Explanation:

Rate of reaction = k[H₂]²[NH3]¹

reaction order in H₂ = 2

reaction order in NH₃ = 1

overall reaction order = 2 + 1 = 3

the initial rate of reaction is 8.0 x 10³ M / s

If the concentration of H₂ is doubled , rate of reaction will become 4 times because rate of reaction varies proportional to square of concentration of hydrogen.

So rate of reaction becomes 32.0 x 10³ M / s

Rate of reaction = k[H₂]²[NH3]¹

By putting the values given,

0.050 M / s = k .66² x .88

k = 0.13.

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