Answer:
1.79 molar
Explanation:
[H+] = 2.5*10-4 M
HOCl = H+ + OCl -
Ka = [H+]*[OCl-]/[HOCl]
[H+] = [OCl-] = 2.5*10-4 M
C (HOCl) = [H+]*[OCl-]/Ka = (2.5*10-4)^2/(3.5*10^-8)
= 1.79 M.
1.79 M of HOCl has the same pH as that of 2.50 × 10-4 molar HNO3.
[H+] = 2.5*10-4 M
HOCl = H+ + OCl -
Ka = [H+]*[OCl-]/[HOCl]
[H+] = [OCl-]
= 2.5*10-4 M
C (HOCl) = [H+]*[OCl-]/Ka
= (2.5*10-4)^2/(3.5*10^-8)
= 1.79 M.
A strong acid is any acid that ionizes absolutely in solutions. this means it gives off the best range of hydrogen ions or protons while placed in an answer.
Strong acids encompass seven essential acids chloric acid, hydrobromic acid, hydrochloric acid, hydroiodic acid, nitric acid, perchloric acid, and sulfuric acid. These can completely dissociate in water, giving them the identity of sturdy acid.
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