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Tommy throws a ball from the balcony of his apartment down to the street. The height of the ball, in meters, is modeled by the function shown in the graph. What's the average rate of change of the height of the ball, in meters per second, while it's in the air?

Respuesta :

Answer:

-1.5 meters per second

Step-by-step explanation:

According to the question, the data provided is as follows

h (o) = 15

And, h (10) = 0

Based on the above information, the average rate of change of the height of the ball is

[tex]h_{avg} = \frac{h(10) - h(0)}{10 - 0}[/tex]

[tex]= \frac{0 - 15}{10}[/tex]

= -1.5 meters per second

Basically we applied the above formula so that we can determine the  average rate of change of the height of the ball and the same is to be considered

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