From the given quadratic equation [tex]x^2 + 10x + 25 = 7[/tex] Thus, the solution is x = -1 and -9.
How to find the roots of a quadratic equation?
Suppose that the given quadratic equation is
[tex]ax^2 + bx + c = 0[/tex]
Then its roots are given as:
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
We have been given a quadratic equation
[tex]x^2 + 10x + 25 = 7[/tex]
[tex]x^2 + 10x + 25 - 7=0\\\\x^2 + 10x + 18[/tex]
The solution of the given equation;
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-10 \pm \sqrt{10^2 - 4\times 18}}{2}\\\\x = \dfrac{-10 \pm \sqrt{100- 36}}{2}\\\\x = \dfrac{-10 \pm \sqrt{64}}{2}\\\\x = \dfrac{-10 \pm 8}{2}\\[/tex]
Therefore, the solution are x = -1 and -9.
Learn more about finding the solutions of a quadratic equation here:
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